A) \[Si{{F}_{4}}\]
B) \[{{H}_{2}}Si{{F}_{4}}\]
C) \[{{H}_{2}}S{{O}_{4}}\],
D) \[{{H}_{2}}Si{{F}_{6}}\]
Correct Answer: D
Solution :
\[3Si{{F}_{4}}+4{{H}_{2}}O\xrightarrow{{}}{{H}_{2}}Si{{F}_{6}}+Si{{(OH)}_{4}}\]
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