A) acetone .
B) ethyl amine
C) acetaldehyde
D) dimethyl amine
Correct Answer: C
Solution :
\[C{{H}_{3}}CN+2[H]\xrightarrow[ether]{HCl}HC\underset{(X)}{\mathop{\equiv }}\,CH\] \[\xrightarrow{\Delta /{{H}_{2}}O}\underset{\begin{smallmatrix} acetaldehyde \\ (Y) \end{smallmatrix}}{\mathop{C{{H}_{3}}CHO}}\,\] \[\therefore \] Y is acetaldehyde.
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