A) 700\[{{m}^{3}}\]
B) 900\[{{m}^{3}}\]
C) 1000\[{{m}^{3}}\]
D) 500\[{{m}^{3}}\]
Correct Answer: B
Solution :
Using standard gas equation, \[\frac{{{p}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{p}_{2}}{{V}_{2}}}{{{T}_{2}}}\] or \[{{V}_{2}}=\frac{{{p}_{1}}{{V}_{1}}{{T}_{2}}}{{{p}_{2}}{{T}_{1}}}\] \[\therefore \] \[{{V}_{2}}=\frac{1\times 500\times (273-3)}{0.5\times (273+27)}\] \[{{V}_{2}}=\frac{1\times 500\times 270}{0.5\times 300}\] \[{{V}_{2}}=900{{m}^{3}}\]
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