A) ethyl formate
B) ethyl chloroformate
C) acetyl chloride
D) carbon dioxide
Correct Answer: B
Solution :
Ethyl acetate is obtained when methyl magnesium bromide reacts with ethyl chloroformate. \[C{{H}_{3}}MgBr+Cl-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-O-{{C}_{2}}{{H}_{5}}\]\[\begin{align} & \xrightarrow{{}}\left[ Cl-\overset{OMgBr}{\mathop{\overset{|}{\mathop{\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,}}\,}}\,-O-{{C}_{2}}{{H}_{5}} \right] \\ & \downarrow \\ \end{align}\]\[\underset{Ethyl\,acetate}{\mathop{C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-O-{{C}_{2}}{{H}_{5}}}}\,+MgBrCl\]
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