2. Solved Papers
  3. BVP Medical

BVP Medical BVP Medical Solved Paper-2008

  • question_answer
    If the electronegativity difference between two atoms A and B is 2.0, then the percentage of co-valent character in the molecule is

    A)  54%                                      

    B)  46%

    C)  23%                                      

    D)  72%

    Correct Answer: B

    Solution :

                     According to Hannay and Smith equation \[\therefore \] % ionic character \[=16({{x}_{A}}-{{x}_{B}})+3.5{{({{x}_{A}}-{{x}_{B}})}^{2}}\] where, \[{{x}_{A}}\] and \[{{x}_{B}}\] are the electronegativitys of the atoms A and B respectively. \[\therefore \]  % ionic character \[=16(2)+3.5{{(2)}^{2}}\]\[=32+14=46%\]c


You need to login to perform this action.
You will be redirected in 3 sec spinner