A) \[C{{H}_{3}}OH+{{(C{{H}_{3}})}_{3}}Cl\]
B) \[C{{H}_{3}}I+{{(C{{H}_{3}})}_{3}}COH\]
C) \[C{{H}_{3}}I+{{(C{{H}_{3}})}_{3}}Cl\]
D) None of the above
Correct Answer: B
Solution :
Here, ether is the solvent. Being less polar, it favours \[{{S}_{N}}2\] reaction and the nucleophile \[{{I}^{-}}\] attacks the \[{{1}^{o}}\] carbon of \[C{{H}_{3}}\].\[{{I}^{-}}+C{{H}_{3}}\overset{\oplus }{\mathop{\underset{H}{\mathop{\underset{|}{\mathop{O}}\,}}\,}}\,-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,}}\,}}\,-C{{H}_{3}}\]\[\xrightarrow{{{S}_{N}}2}C{{H}_{3}}I+\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C{{H}_{3}}-C-OH}}\,}}\,}}\,}}\,\]
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