A) 1 : 2 : 3
B) 2 : 4 : 6
C) 1 : 4 : 9
D) 1 : 3 : 5
Correct Answer: C
Solution :
For hydrogen and H-like atom Bohrs radius of orbit \[{{r}_{n}}=\frac{{{n}^{2}}{{h}^{2}}}{4{{\pi }^{2}}kZm{{e}^{2}}}=\frac{{{n}^{2}}{{h}^{2}}{{\varepsilon }_{0}}}{\pi mZ{{e}^{2}}}=0.53\frac{{{n}^{2}}}{Z}\overset{\text{o}}{\mathop{\text{A}}}\,\] \[\Rightarrow \] \[{{r}_{n}}=\frac{{{n}^{2}}}{Z}\] \[\therefore \] Ratio between Bohr radii \[=1:4:9:......\] where \[n=1,2,3...\]
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