A) \[E\alpha {{J}^{-1}}\]
B) \[E\alpha J\]
C) \[E\alpha \frac{1}{{{J}^{2}}}\]
D) \[{{E}^{2}}\alpha \frac{1}{J}\]
Correct Answer: B
Solution :
Current density relates with electric field as \[\overrightarrow{\mathbf{J}}=\sigma \overrightarrow{\mathbf{E}}=\frac{\overrightarrow{\mathbf{E}}}{\rho };\]where \[\sigma \] = conductivity and \[\rho \]= resistivity or specific resistance of substance.
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