BVP Medical BVP Medical Solved Paper-2009

  • question_answer
    Three masses of 2 kg, 4 kg and 4 kg are placed at the three points (1, 0, 0), (1, 1, 0) and (0. 1, 0) respectively. The position vector of its centre of mass is

    A) \[\frac{3}{5}\mathbf{\hat{i}}+\frac{4}{5}\mathbf{\hat{j}}\]                        

    B) \[(3\mathbf{\hat{i}}+\mathbf{\hat{j}})\]

    C) \[\frac{2}{5}\mathbf{\hat{i}}+\frac{4}{5}\mathbf{\hat{j}}\]                        

    D) \[\frac{1}{5}\mathbf{\hat{i}}+\frac{3}{5}\mathbf{\hat{j}}\]

    Correct Answer: A

    Solution :

    \[{{\overrightarrow{\mathbf{v}}}_{cm}}=\frac{{{m}_{1}}\,{{\overrightarrow{\mathbf{v}}}_{1}}+{{m}_{2}}\,{{\overrightarrow{\mathbf{v}}}_{2}}\,}{{{m}_{1}}+{{m}_{2}}}\] \[=\frac{2\times (1\,\,\mathbf{\hat{i}})+4(1\,\,\mathbf{\hat{i}}+i\,\,\mathbf{\hat{j}})+4(1\,\mathbf{\hat{j}})}{2+4+4}=\frac{3}{5}\mathbf{\hat{i}}+\frac{4}{5}\mathbf{\hat{j}}\]


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