BVP Medical BVP Medical Solved Paper-2009

  • question_answer
    What is \[\Delta {{G}^{o}}\] at \[298K\] for the reaction, \[+2{{H}_{2}}O(l)+C{{d}^{2+}}(aq)\]?

    A)  \[-271\,kJ\]                       

    B)  \[1.403J\]

    C)  \[-135kJ\]          

    D)  \[-115kJ\]

    Correct Answer: A

    Solution :

                    \[2{{e}^{-}}+2VO_{2}^{+}+4{{H}^{+}}\xrightarrow{{}}2V{{O}^{2+}}+2{{H}_{2}}O;\] \[\Delta {{E}^{o}}=1.0V\]                      ??.(i)                 \[Cd\xrightarrow{{}}C{{d}^{2+}}+2{{e}^{-}}{{;}^{*}}\Delta {{E}^{o}}=+0.40V\]  ?(ii) On adding Eq (i) and (ii), we get \[2VO_{2}^{+}+4{{H}^{+}}+Cd\to 2V{{O}^{2+}}+2{{H}_{2}}O+C{{d}^{2+}};\]         \[E_{cell}^{o}=1.0+0.40=1.40V\]                 \[\Delta {{G}^{o}}=-nFE_{cell}^{o}\]                 \[=-2\times 96500\times 1.4\]                 \[=-270200J\]                 \[=-271kJ\] Since in this Q. \[{{E}^{o}}\] values are not given, it is incorrect. These values are taken from reference books.


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