A) \[\frac{m{{v}^{3}}}{4\sqrt{2g}}\]
B) \[\frac{m{{v}^{2}}}{\sqrt{2g}}\]
C) \[m(2g{{h}^{3}})\]
D) \[mg\left[ \frac{b}{2} \right]\]
Correct Answer: D
Solution :
Here, \[{{m}^{2}}/{{s}^{2}}\] \[{{m}^{2}}/{{s}^{2}}\] \[{{m}^{2}}/{{s}^{2}}\] \[{{m}^{2}}/{{s}^{2}}\] \[\frac{mgR\sin \theta }{{{B}^{2}}{{l}^{2}}}\] \[\frac{mgR\sin \theta }{B{{l}^{3}}}\] \[\frac{mgR\sin \theta }{{{B}^{2}}{{l}^{5}}}\] \[\frac{mgR\sin \theta }{B{{l}^{4}}}\]
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