BVP Medical BVP Medical Solved Paper-2010

  • question_answer
    A particle of mass m is projected with avelocity v making an angle of 45° with thehorizontal. The magnitude of angularmomentum of the projectile about an axis ofprojection when the particle is of maximumheight h is

    A)  zero                     

    B)  \[\frac{v}{3c}\]

    C)  \[\frac{v}{4c}\]                

    D)  \[x=7t+4{{t}^{2}}\]

    Correct Answer: B

    Solution :

                    Maximum height attained \[\frac{{{\varepsilon }_{0}}A}{d}\left[ \frac{2}{{{k}_{1}}}+\frac{{{k}_{2}}{{k}_{3}}}{{{k}_{2}}+{{k}_{3}}} \right]\] \[\frac{{{\varepsilon }_{0}}A}{d}\left[ \frac{2}{{{k}_{1}}}+\frac{{{k}_{2}}+{{k}_{3}}}{{{k}_{2}}{{k}_{3}}} \right]\] \[1.81\times {{10}^{-5}}wb\] At highest point, momentum \[0.904\times {{10}^{-5}}wb\]                                                 \[5.43\times {{10}^{-5}}wb\] Angular momentum \[2\times {{10}^{-2}}{{m}^{2}}\]                                 \[{{10}^{6}}\]


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