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BVP Medical BVP Medical Solved Paper-2010

  • question_answer
    An electron and a photon possess the same de-Broglie wavelength. If \[\Omega \] and\[\frac{{{T}^{2}}}{2x}\]respectively are the energies of electron andphoton and v and c are their respective velocities, then \[\frac{{{T}^{2}}}{2k}\] is equal to

    A) \[\frac{2k}{{{T}^{2}}}\]                 

    B) \[\frac{2{{T}^{2}}}{k}\]

    C) \[{{s}^{2}}\]                       

    D) \[{{m}^{2}}/{{s}^{2}}\]

    Correct Answer: B

    Solution :

                    de-Broglie wavelength \[{{10}^{12}}\] \[2.5\times {{10}^{7}}\] or  \[1.25\times {{10}^{7}}\]       ...(i) But       \[2.5\times {{10}^{8}}\] or  \[1.25\times {{10}^{6}}\] From Eq. (i)                 \[\frac{G}{19}\] or            \[\frac{G}{20}\] or \[E=16T-0.04{{T}^{2}}\mu V.\] or            \[{{T}_{i}}\]


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