BVP Medical BVP Medical Solved Paper-2010

  • question_answer
    The x and y coordinates of a particle at anytime t are given by \[{{m}^{2}}/{{s}^{2}}\]and\[{{m}^{2}}/{{s}^{2}}\],where x and y are in metre and t is insecond. The acceleration of the particle att = 5 s is

    A)  zero                     

    B)  8 m/\[{{m}^{2}}/{{s}^{2}}\]

    C)  20 m/\[\frac{mgR\sin \theta }{{{B}^{2}}{{l}^{2}}}\]                         

    D)  40 m/\[\frac{mgR\sin \theta }{B{{l}^{3}}}\]

    Correct Answer: B

    Solution :

                    Acceleration  \[{{200}^{0}}C\] \[{{300}^{0}}C\] Here      \[0.18\times {{10}^{-3}}{{C}^{-1}}\] Hence       \[\left( \frac{0.4}{\pi } \right)\]


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