BVP Medical BVP Medical Solved Paper-2010

  • question_answer
    The wave impedance of free space is

    A)  zero                     

    B)  376.6\[{{y}_{1}}=a\sin \frac{2\pi }{\lambda }(vt-x)\]

    C)  1883\[{{y}_{2}}=b\sin \frac{2\pi }{\lambda }[(vt-x)+{{x}_{0}}]\]                

    D)  3776\[{{x}_{0}}=(\lambda /2)\]

    Correct Answer: B

    Solution :

                    In the case of a dielectric (where conductivity is zero) wave impedance of free space \[\frac{v}{c}\] In free space \[\frac{v}{2c}\]  and \[\varepsilon =8.54\times {{10}^{-12}}F/m.\] So, the value of wave impedance in free space,                 \[{{Z}_{0}}\approx 377\Omega \]


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