question_answer

The total number of isomers for \[{{C}_{4}}{{H}_{8}}\] is

A)  5                                            

B)  6

C)  7                                            

D)  8

Correct Answer: B

Solution :

                The possible isomers of \[{{C}_{4}}{{H}_{8}}\] are as (i) \[\underset{1-butene}{\mathop{C{{H}_{3}}C{{H}_{2}}CH=C{{H}_{2}}}}\,\] (ii) \[\underset{trans\,2-butene}{\mathop{C{{H}_{3}}\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,=\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,-C{{H}_{3}}}}\,\] (iii) \[\underset{cis\,2-butene}{\mathop{C{{H}_{3}}CH=CHC{{H}_{3}}}}\,\] (iv) \[\underset{2-methyl\,propane}{\mathop{C{{H}_{3}}\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}}}\,\] (v)    and (vi)