A) \[{{100.52}^{o}}C\]
B) \[{{101.04}^{o}}C\]
C) \[{{99.48}^{o}}C\]
D) \[{{98.96}^{o}}C\]
Correct Answer: B
Solution :
\[\Delta {{T}_{b}}=i\,{{K}_{b}}m=2\times 0.52\times 1={{1.04}^{o}}C\] \[\Delta {{T}_{b}}={{T}_{b}}-{{T}^{o}}\] \[\Rightarrow \]\[{{1.04}^{o}}C={{T}_{b}}-{{100}^{o}}C\] \[\therefore \] \[{{T}_{b}}={{101.04}^{o}}C\]
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