A) \[C{{u}^{+}}\]
B) \[C{{o}^{2+}}\]
C) \[N{{i}^{2+}}\]
D) \[F{{e}^{3+}}\]
Correct Answer: A
Solution :
Colour of the transition elements is generally because of the presence of unpaired d electrons which result in d-d transition. \[C{{u}^{+}}=[Ar]3{{d}^{10}}\] (no unpaired d electron) \[C{{o}^{2+}}=[Ar]3{{d}^{7}}\] (three unpaired d electrons) \[N{{i}^{2+}}[Ar]3{{d}^{8}}\] (two unpaired d electron) \[F{{e}^{3+}}=[Ar]3{{d}^{5}}\] (five unpaired d electrons) \[C{{u}^{+}}\] has no unpaired d electrons, thus d-d transition is not possible in it. Hence, it is colourless.
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