A) \[C{{H}_{2}}{{O}_{2}}\]
B) \[C{{H}_{2}}O\]
C) \[C{{H}_{4}}O\]
D) \[{{C}_{2}}{{H}_{4}}{{O}_{2}}\]
Correct Answer: B
Solution :
\[C:H:O=\frac{24}{12}:\frac{4}{1}:\frac{32}{16}=2:4:2\]or \[1:2:1\] \[\therefore \]Empirical formula \[=C{{H}_{2}}O\]
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