A) \[{{H}_{2}}\] is evolved at cathode
B) \[S{{O}_{2}}\] is produced at anode
C) \[{{O}_{2}}\] is obtained at cathode
D) \[S{{O}_{2}}\] is produced at cathode
Correct Answer: A
Solution :
\[{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}2{{H}^{+}}+SO_{4}^{2-}\] At cathode \[2{{H}^{+}}+2{{e}^{-}}\xrightarrow{{}}{{H}_{2}}\] At anode \[4O{{H}^{-}}\xrightarrow{{}}{{O}_{2}}+2{{H}_{2}}O+4{{e}^{-}}\]
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