A) \[-170\,kJ\,mo{{l}^{-1}}\]
B) \[-260\,kJ\,mo{{l}^{-1}}\]
C) \[-400\,kJ\,mo{{l}^{-1}}\]
D) \[-450\,kJ\,mo{{l}^{-1}}\]
Correct Answer: A
Solution :
\[H-\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,=\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,-H+H-H\to H-\underset{H}{\mathop{\underset{|}{\mathop{\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-\underset{H}{\mathop{\underset{|}{\mathop{\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-H\] \[\Delta {{H}_{reaction}}=\Sigma BE\text{(Reactants)-}\Sigma \text{BE(Products)}\]\[=[BE(4C-H)+BE(C=C)+BE(H-H)]\] \[-[BE\,(6C-H)+BE(C-C)]\] \[=BE(C=C)+BE(H-H)-BE(2C-H)\]\[-BE(C-C)\] \[=600+400-2\times 410-350\] \[=1000-1170=-170kJ\,mo{{l}^{-1}}\]
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