2. Solved Papers
  3. BVP Medical

BVP Medical BVP Medical Solved Paper-2010

  • question_answer
    The rate constant for the reaction,\[2{{N}_{2}}{{O}_{5}}\xrightarrow{{}}4N{{O}_{2}}+{{O}_{2}}\] is \[3.0\times {{10}^{-5}}{{s}^{-1}}\]. If the rate is \[2.40\times {{10}^{-5}}\,mol\,{{L}^{-1}}\,{{s}^{-1}}\] then the concentration of \[{{N}_{2}}{{O}_{5}}\] (in \[mol\,{{L}^{-1}}\]) is

    A)  \[1.4\]                                 

    B)  \[1.2\]

    C)  \[0.04\]                              

    D)  \[0.8\]

    Correct Answer: D

    Solution :

                    For a first order reaction, \[rate=k[{{N}_{2}}{{O}_{5}}]\]                 \[2.4\times {{10}^{-5}}=3.0\times {{10}^{-5}}[{{N}_{2}}{{O}_{5}}]\] \[[{{N}_{2}}{{O}_{5}}]=\frac{2.4\times {{10}^{-5}}}{3.0\times {{10}^{-5}}}=0.8mol\,{{L}^{-1}}\] (The order of reaction is found from the given units of k.)


You need to login to perform this action.
You will be redirected in 3 sec spinner