A) 2 kg
B) 0.2 kg
C) 5 kg
D) 10 kg
Correct Answer: A
Solution :
Mass of block \[\mu F\] Coefficient of friction \[\mu F\] Force of friction \[\mu F\] where R is reaction of plane. ie, \[\mu F\] \[\mu F\] \[[M{{L}^{-1}}{{T}^{-2}}]\] To start motion force due to B must be equal to F. ie, \[[ML{{T}^{-1}}]\] \[[ML{{T}^{-2}}]\] \[[M{{L}^{2}}{{T}^{-2}}]\] \[\frac{3aT}{2}\]
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