question_answer

The moment of inertia of a solid cylinder of mass M and radius R about a line parallel to the axis of the cylinder and lying on the surface of the cylinder is

A) \[\theta \]                          

B) \[i\alpha \tan \theta \]

C) \[i\alpha \theta \]                           

D) \[i\alpha {{\theta }^{2}}\]

Correct Answer: C

Solution :

                Moment of inertia of solid cylinder about ifs central axis \[\frac{3}{5}M{{R}^{2}}\] According to theorem of parallel axes                 \[\frac{3}{2}M{{R}^{2}}\]                 \[\frac{5}{2}M{{R}^{2}}\]