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BVP Medical BVP Medical Solved Paper-2011

  • question_answer
    A particle is making uniform circular motion with angular momentum J. If its kinetic energy is made half and angular frequency be doubled, its new angular momentum will be

    A)  2 J                                         

    B)  4 J  

    C)  J/2                                        

    D)  J/4

    Correct Answer: D

    Solution :

                    Rotational kinetic energy, \[5.26\times {{10}^{3}}\] Angular momentum \[({{R}_{e}}=6.37\times {{10}^{6}}m)\] \[mg{{R}_{e}}\,.\]            \[{{R}_{e}}\] \[{{R}_{e}}\]       \[-2mg{{R}_{e}}\] \[2mg{{R}_{e}}\]              \[1\frac{1}{2}mg{{R}_{e}}\]


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