A) \[{{O}_{2}}\]
B) \[F=i(i\times B)=0\]
C) \[\tan \theta =\frac{V}{H}\]
D) \[\frac{1}{2}iBL\]
Correct Answer: D
Solution :
Change in gravitational potential energy \[\overset{0}{\mathop{A}}\,\] \[\overset{0}{\mathop{A}}\,\] \[\overset{0}{\mathop{A}}\,\] Substituting \[\overset{0}{\mathop{A}}\,\] \[y=5\sin \frac{\pi x}{3}\cos 40\pi t\] \[5\times {{10}^{14}}\] \[\overset{0}{\mathop{A}}\,\] \[\overset{0}{\mathop{A}}\,\] \[\overset{0}{\mathop{A}}\,\]
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