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BVP Medical BVP Medical Solved Paper-2011

  • question_answer
    When \[{{F}_{2}}\] reacts with hot and concentrated alkali, the following will be obtained (i) \[O{{F}_{2}}\]                               (ii) \[{{O}_{2}}\] (iii) \[{{H}_{2}}O\]                            (iv) \[NaF\]

    A)  (i), (iii) and (iv)                 

    B)  (ii), (iii) only

    C)  (ii), (iii) and (iv)                

    D)  All of these

    Correct Answer: C

    Solution :

                    Fluorine does not form oxyacids as it is most electronegative element of the Periodic Table. \[2{{F}_{2}}+4NaOH\xrightarrow{Hot}4NaF+{{O}_{2}}+2{{H}_{2}}O\] \[{{F}_{2}}+2NaOH\xrightarrow{Cold}2NaF+\frac{1}{2}{{O}_{2}}+{{H}_{2}}O\] \[\therefore \] \[{{F}_{2}}\] reacts with hot \[NaOH\] to give \[NaF\], \[{{O}_{2}}\] and  \[{{H}_{2}}O\].


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