BVP Medical BVP Medical Solved Paper-2011

  • question_answer
    \[2{{N}_{2}}{{O}_{5}}\xrightarrow{{}}4N{{O}_{2}}+{{O}_{2}}\]. The rate of reaction in terms of \[{{N}_{2}}{{O}_{5}}\] will be

    A)  \[-\frac{d[{{N}_{2}}{{O}_{5}}]}{dt}\]

    B)  \[-\frac{1}{4}\frac{d[{{N}_{2}}{{O}_{5}}]}{dt}\]

    C)  \[-\frac{1}{2}\frac{d[{{N}_{2}}{{O}_{5}}]}{dt}\]

    D)  \[-\frac{1}{3}\frac{d[{{N}_{2}}{{O}_{5}}]}{dt}\]

    Correct Answer: C

    Solution :

                    Rate of reaction \[=-\frac{1}{x}\frac{d[R]}{dt}=+\frac{1}{y}\frac{d[p]}{dt}\] [where, x and y are the stoichiometric coefficients of reactant R and product P respectively] \[\therefore \] \[Rate=\frac{-d[{{N}_{2}}{{O}_{5}}]}{2dt}=+\frac{1}{4}\frac{d[N{{O}_{2}}]}{dt}\]                                 \[=+\frac{d[{{O}_{2}}]}{dt}\]


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