A) \[{{O}^{2-}}\]
B) \[{{F}^{-}}\]
C) \[L{{i}^{+}}\]
D) \[A{{l}^{3+}}\]
Correct Answer: C
Solution :
\[N{{a}^{+}}=2,8\] (10 electrons) \[{{O}^{2-}}=2,8\] (10 electrons) \[{{F}^{-}}=2,8\] (10 electrons) \[L{{i}^{+}}=2\] (2 electrons) \[A{{l}^{3+}}=2,8\] (10 electrons) Thus, sodium cation differs from \[L{{i}^{+}}\] in number ;
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