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BVP Medical BVP Medical Solved Paper-2012

  • question_answer
    Two bodies A and B having temperatures \[0.31\] and \[0.81\] are radiating heat to the surrounding. The surrounding temperature is \[0.42\]. The ratio of rate of heat radiation of A to that of B is

    A)  \[{{r}_{A}}\]                     

    B)  \[{{r}_{B}}\]

    C)  \[{{v}_{A}}\]                                     

    D)  \[{{v}_{B}}\]

    Correct Answer: A

    Solution :

                    If temperature of surrounding is considered, then net loss of energy of a body by radiation \[\frac{2v(n-1)}{n}\]                 \[\frac{v(n-1)}{n}\]         \[\frac{v(n+1)}{n}\]                 \[\frac{2v(n+1)}{n}\]      \[F=q(v\times B)\]                                 \[F=q(v\times B)\]                                 \[{{327}^{o}}C\]


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