A) \[1:9\]
B) \[1:16\]
C) \[6m/s\]
D) \[4m/s\]
Correct Answer: D
Solution :
Velocity of the molecules of nitrogen \[3m/{{s}^{2}}\] \[-3m/{{s}^{2}}\] \[0.3m/{{s}^{2}}\] \[7=\sqrt{\frac{{{T}_{H}}\times 28}{2\times 300}}\] \[49=\frac{{{T}_{H}}\times 28}{600}\] \[{{T}_{H}}=\frac{49\times 600}{28}=1050K\]You need to login to perform this action.
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