A) \[2m/s\]
B) \[1m/s\]
C) \[10m/s\]
D) \[7m/s\]
Correct Answer: A
Solution :
\[\beta =\frac{{{Q}_{2}}}{W}=\frac{{{T}_{L}}}{{{T}_{H}}-{{T}_{L}}}\] \[{{Q}_{2}}=\frac{273\times 1}{303-273}\] \[=\frac{273}{30}=9J\] Heat delivered to the surrounding \[{{Q}_{1}}={{Q}_{2}}+W=9+1=10J\]You need to login to perform this action.
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