BVP Medical BVP Medical Solved Paper-2012

  • question_answer
    A body at a temperature of \[0.81\] and has surface area\[0.42\], radiates 300 J of energy each minute. The emissivity is (Given : Boltzman constant \[{{r}_{A}}\])

    A)  e = 0.18          

    B)  e = 0.02

    C)  e = 0.2           

    D)  e = 0.15

    Correct Answer: A

    Solution :

                    \[Q=E\,\,\,\,At\,=e\sigma ({{T}^{4}}-T_{0}^{4})At\] where, t is time \[{{T}_{0}}\]= temperature of surrounding When,      \[T>{{T}_{0}}\]                                 \[Q=e\sigma {{T}^{4}}\,\,At\] \[300=e\times (5.67\times {{10}^{-8}}){{(1000)}^{4}}\]                                 \[(5.00\times {{10}^{-4}})(60)\] or            \[e=0.18\]


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