A) \[4m/s\]
B) \[2m/s\]
C) \[1m/s\]
D) \[10m/s\]
Correct Answer: A
Solution :
\[c=MB\sin \theta \] \[=(m\times 2l)\times 2\times {{10}^{-5}}\sin {{30}^{o}}\] \[=15\times 10\times {{10}^{-2}}\times 2\times {{10}^{-5}}\times \frac{1}{2}\] \[=1.5\times {{10}^{-5}}Nm\]
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