A) \[6M\]
B) \[18M\]
C) \[10M\]
D) \[4M\]
Correct Answer: B
Solution :
98% \[{{H}_{2}}S{{O}_{4}}\] means 98 g \[{{H}_{2}}S{{O}_{4}}\] in 100 g solution i.e., volume of the solution \[=\frac{100}{1.8}mL=55.55mL\] \[98\text{ }g\text{ }{{H}_{2}}\text{S}{{\text{O}}_{4}}=1\text{ }mol\] \[\therefore \] \[Molarity=\frac{moles\,of\,the\,solute}{volume\,of\,solution\,(in\,mL)}\] \[\times 1000\] \[=\frac{1}{55.55}\times 1000=18M\]
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