A) \[{{O}_{2}}\]
B) \[{{N}_{2}}\]
C) \[He\]
D) \[N{{H}_{3}}\]
Correct Answer: A
Solution :
The electronic configuration of 02 molecule is as \[{{O}_{2}}:KK{{(\sigma 2s)}^{2}}{{(\overset{*}{\mathop{\sigma }}\,2s)}^{2}}{{(\sigma 2{{p}_{z}})}^{2}}{{(\pi 2{{p}_{x}})}^{2}}{{(\pi 2{{p}_{y}})}^{2}}\]\[{{(\overset{*}{\mathop{\pi }}\,2{{p}_{x}})}^{1}}{{(\overset{*}{\mathop{\pi }}\,2{{p}_{y}})}^{1}}\] In the \[{{O}_{2}}\] molecule there are two unpaired electrons, hence it shows paramagnetic character.
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