A) \[C{{H}_{3}}-C{{H}_{2}}-C\equiv C-CH\equiv C{{H}_{2}}\]
B) \[C{{H}_{3}}-C\equiv C-CH=CH-C{{H}_{3}}\]
C) \[C{{H}_{3}}C{{H}_{2}}-CH=CH-C\equiv CH\]
D) \[C{{H}_{3}}-C\equiv C-C{{H}_{2}}-CH=C{{H}_{2}}\]
Correct Answer: B
Solution :
The structure of hexa-2-ene-4-yne is as \[C{{H}_{3}}-C\equiv C-CH=CH-C{{H}_{3}}\]
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