A) toluene
B) phenol
C) benzene
D) benzoic acid
Correct Answer: C
Solution :
On heating a mixture of sodium benzoate and sodalime, benzene is formed. \[\underset{\begin{smallmatrix} sodium \\ benzoate \end{smallmatrix}}{\mathop{{{C}_{6}}{{H}_{5}}COONa}}\,+NaOH\xrightarrow[Decarboxylation]{CaO,\,\,Heat}\]\[\underset{benzene}{\mathop{{{C}_{6}}{{H}_{6}}}}\,+N{{a}_{2}}C{{O}_{3}}\]
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