question_answer

In the following reaction,\[2C{{H}_{2}}=C{{H}_{2}}+{{S}_{2}}C{{l}_{2}}\to \Pr oduct\]The product is

A)  mustard gas     

B)  lewisite

C)  polythene         

D)  Teflon

Correct Answer: A

Solution :

                \[\underset{ethene}{\mathop{2C{{H}_{2}}}}\,=C{{H}_{2}}+{{S}_{2}}C{{l}_{2}}\xrightarrow{{}}\]