A) \[p+\frac{1}{2}\rho {{\upsilon }^{2}}+\rho gh=k\]
B) \[\frac{4{{v}^{2}}}{5g}\]
C) independent of x
D) \[\frac{4g}{5{{v}^{2}}}\]
Correct Answer: A
Solution :
In simple harmonic motion when a particle is displaced to a position from its mean position, then its kinetic energy gets converted into potential energy and vice-versa. Hence, total energy of a particle remains constant or the total energy in simple harmonic motion does not depend on displacement x.
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