A) \[+1.6\times {{10}^{-16}}C\]
B) \[{{F}_{1}}\]
C) \[{{F}_{2}}\]
D) None of these
Correct Answer: D
Solution :
The potential at each point on the circular path will be equal. So, work done = q \[2A\] potential difference \[4A\] \[6A\]
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