A) \[5l\,and\,\,3l\]
B) \[_{0}^{1}n+_{92}^{235}U\to _{92}^{236}U\to _{40}^{98}Zr+_{52}^{136}Te+2_{0}^{1}n\]
C) \[_{42}^{98}{{M}_{0}}\]
D) \[_{54}^{136}X\]
Correct Answer: A
Solution :
\[150s\] or \[200s\] \[4L\] \[2L\] \[\frac{L}{2}\] \[={{\left( \frac{1+2}{1-2} \right)}^{2}}=\frac{9}{1}\] \[{{l}_{\max }}=9l\] and \[{{l}_{\min }}=l\]
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