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BVP Medical BVP Medical Solved Paper-2013

  • question_answer
    Calculate the total energy released during a fission reaction \[\beta \] The resulting fission fragments are unstable hence, decay into stable end products \[=1.0087\text{ }amu\] and \[_{92}^{235}U=236.0526amu\]by successive emission of \[_{42}^{98}{{M}_{0}}=97.9054amu\]-particles.   Take   mass   of  neutron \[_{54}^{136}Xe=135.9170amu\], mass of \[198MeV\], mass of \[220\text{ }MeV\] and mass of \[185\text{ }MeV\]

    A)  \[230\text{ }MeV\]                       

    B)  \[{{10}^{-10}}m,\]

    C)  \[4.2\times {{10}^{15}}\text{ }Hz\]                         

    D)  \[0.36\times {{10}^{15}}Hz\]

    Correct Answer: A

    Solution :

                    \[_{0}^{1}n+_{92}^{235}U\xrightarrow{{}}_{92}^{98}{{M}_{0}}+_{84}^{136}Xe+{{2}^{1}}{{n}_{0}}\] \[(1.0087+235.0439)\]                 \[=(97.9034+135.917+2.0174)\]                 \[\Delta m=0.2128\] Total energy released during a fission reaction                 \[=0.2128\times 931MeV\]                 \[=198Mev\]


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