A) 12
B) 10
C) 22
D) 20
Correct Answer: B
Solution :
The time period of a simple pendulum is \[198MeV\] \[220\text{ }MeV\]and \[185\text{ }MeV\] \[230\text{ }MeV\] Let after n oscillations, pendulums are in same phase, then \[{{10}^{-10}}m,\] \[4.2\times {{10}^{15}}\text{ }Hz\]You need to login to perform this action.
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