BVP Medical BVP Medical Solved Paper-2013

  • question_answer
    A non-conducting ring of radius r has charge per unit length \[4A\]. A magnetic field perpendicular to plane of the ring changes at rate dB /dt. Torque experienced by the ring is

    A)  \[6A\]                                 

    B)  \[1.33\times {{10}^{-7}}kg\]

    C)  \[19.8\times {{10}^{-7}}kg\]      

    D)  zero

    Correct Answer: A

    Solution :

                    \[e=\frac{d\phi }{dt}=\pi {{r}^{2}}\frac{dB}{dt}\] \[E(2\pi r)=\pi {{r}^{2}}\frac{dB}{dt}\] \[E=\frac{1}{2}r\frac{dB}{dt}\] \[dF=\lambda dsE\] \[d\tau =\lambda dsE\] \[d\tau =r\lambda dsE\] \[\tau =\lambda rE\int{ds}=\lambda E\,\,2\pi r\] \[=2\pi {{r}^{2}}\lambda \frac{1}{2}r\frac{dB}{dt}=\pi {{r}^{3}}\lambda \frac{dB}{dt}\]


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