A) \[\frac{m{{L}^{2}}}{12}\]
B) \[\frac{m{{L}^{2}}}{6}\]
C) \[\frac{1}{2}\]
D) \[\frac{2}{3}\]
Correct Answer: B
Solution :
\[{{\lambda }_{m}}\,\,\,T=b\] \[{{\lambda }_{m}}\,\,\frac{b}{T}=\frac{0.2898\times {{10}^{-2}}}{6032.25}\] \[=\frac{2898}{6032.25}\times {{10}^{-6}}\] \[=0.48042\times {{10}^{-6}}\] \[=4804.2\times {{10}^{-10}}\] \[=4804.2\overset{\text{o}}{\mathop{\text{A}}}\,\]
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