A) \[{{O}_{3}}\]
B) \[NO_{2}^{-}\]
C) \[NO_{2}^{+}\]
D) \[S{{O}_{2}}\]
Correct Answer: C
Solution :
\[NO_{2}^{+}\] has linear shape due to sp-hybridisation of N in \[NO_{2}^{+}\] \[O={{N}^{+}}=O\]while \[{{O}_{3}},S{{O}_{2}}\] and \[NO_{2}^{-}\] have angular shape due to \[s{{p}^{2}}\]hybridisation.
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