A) \[1\]
B) \[2\]
C) \[3\]
D) \[4\]
Correct Answer: B
Solution :
\[d=\frac{ZM}{{{a}^{3}}.{{N}_{0}}}\] or \[Z=\frac{d{{a}^{3}}\,{{N}_{0}}}{M}\]\[=\frac{0.53g\,c{{m}^{-3}}\times {{(3.5\times {{10}^{-8}}cm)}^{3}}\times 6.023\times {{10}^{3}}mo{{l}^{-1}}}{100\times 0.0832}\]\[=1.97=2\]
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