A) \[125.0g\]
B) \[206.85\text{ }g\]
C) \[346.70\text{ }g\]
D) \[562.42\text{ }g\]
Correct Answer: D
Solution :
\[\Delta {{T}_{b}}=100-95={{5}^{o}}\] \[\because \] \[\Delta {{T}_{b}}=i{{K}_{b}}m\] or \[m=\frac{\Delta {{T}_{b}}}{i{{K}_{b}}}=\frac{5}{2\times 0.52}=4.807\] 1000 g solution contain = 4.807 mol \[NaCl\] \[=4.807\times 58.5g\,NaCl\] \[\therefore \] 2000 g solution will contain \[=\frac{4.807\times 58.5\times 2000}{1000}\] \[=562.42g\,NaCl\]
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