A) \[\text{4 }km/h\]
B) \[\text{5 }km/h\]
C) \[{{10}^{-6}}{{m}^{2}}\]
D) \[{{10}^{29}}\]
Correct Answer: D
Solution :
Initial angular momentum of ring \[\text{5 }km/h\] Final angular momentum of ring and two particle system \[{{10}^{-6}}{{m}^{2}}\] If there is no torque on the system, therefore angular momentum remains constant. \[{{10}^{29}}\] \[250\times {{10}^{-3}}m/s\]
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